Jeff took 8 hours to travel from Town A to Town B.
Nick took 12 hours to travel from Town B to Town A
Both Jeff and Nick started at 0930.
At what time would they pass each other on the way?
Actually, this is a relatively simple question... If you know how to do it, it is very easy.
The solution is below.
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METHOD 1:
Let the distance between Town A and Town B be 24km.
Speed of Jeff : Dist/Time = 24km/8h = 3km/h
Speed of Nick : Dist/Time = 24km/12h = 2km/h
Time taken to meet = Dist/Total speed
= 24/ 3+2
= 24/5
= 4.8h = 4h 48 min
0930 --4h 48 min ------ 1418--> ANSWER!
Simple???
METHOD 2 :
Jeff : 8h --> 1 journey
1h --> 1/8 journey
Nick : 12h --> 1 journey
1h --> 1/12 journey
1/8 + 1/12 = 3/24 + 2/24 = 5/24
5/24 journey = 1h
24/24 journey = 24/5 h = 4.8h = 4h 48min
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I think that all your maths posts are well done overall. The posts have both brief explaination and also questions and answers. This allows the readers to understand the topic easily.
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